Multiple choice

The radius of a circle with O center is 10 cm, PQ and PR are chords of 12 cm each. PO cuts the chord QR at point S. What is the length of OS?

  1. 3.2

  2. 3

  3. 2.8

  4. 2.5

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

In a circle of radius 10 cm, two chords PQ and PR of equal length (12 cm) create symmetry. The distance from center to each 12 cm chord is d = √(10² - 6²) = 8 cm (since half-chord = 6 cm). Given the geometry, OS = 10 - distance to chord QR. With symmetric configuration, OS ≈ 2.8 cm.