Multiple choice

In each of the following questions, two equations are given. You have to solve them and ( (I) ) (2x^2 + 17x + 30 = 0) ( (II) ) (6y^2 - 5y - 6 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve (I): 2x² + 17x + 30 = 0 factors to (2x + 5)(x + 6) = 0, giving x = -2.5 or x = -6. Solve (II): 6y² - 5y - 6 = 0 factors to (3y - 4)(2y + 3) = 0, giving y = 4/3 or y = -1.5. Comparing: x = -2.5 < y = -1.5 (x < y true); x = -2.5 < y = 4/3 (x < y true); x = -6 < both y values. So x < y always.

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