Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $( (I) x^2 – 13x + 40 = 0 )$ $( (II) y^2 – 10y + 21 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation (I): x^2 - 13x + 40 = 0 factors as (x-5)(x-8) = 0, giving x = 5 or 8. Solving equation (II): y^2 - 10y + 21 = 0 factors as (y-3)(y-7) = 0, giving y = 3 or 7. When x=5, y could be 3 (x>y) or 7 (xy). Since the relationship varies depending on which values we pick, it cannot be uniquely determined.

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