Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $( (I) x^2 – 16x + 63 = 0 )( (II) y^2 – 21y + 110 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): x^2 - 16x + 63 = 0 factors as (x-7)(x-9) = 0, giving x = 7 or 9. Solving equation (II): y^2 - 21y + 110 = 0 factors as (y-10)(y-11) = 0, giving y = 10 or 11. Comparing all possible values, both solutions for x (7 and 9) are less than both solutions for y (10 and 11), so x < y always holds.