Multiple choice

In each of the following questions, two equations are given, you have to solve them and ( (I) ) ( x^2 – 14x + 48 = 0 ) ( (II) ) ( y^2 – 23y + 132 = 0 )

  1. if x > y

  2. if x ≥ y

  3. if x < y

  4. if x ≤ y

  5. if x = y or relationship can not be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): x² - 14x + 48 = 0 gives x = 6 or x = 8. Solving equation (II): y² - 23y + 132 = 0 gives y = 11 or y = 12. Comparing the roots: maximum x value is 8 while minimum y value is 11, so x < y for all combinations of roots.

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