Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $( (I). x^2 – 12x + 32 = 0 )$ $( (II). y^2 = 324 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve x² - 12x + 32 = 0: (x - 4)(x - 8) = 0, so x = 4 or x = 8. Solve y² = 324: y = ±18. When x = 4 or 8 and y = -18, we have x > y. When y = +18, we have x < y. Since the relationship depends on which values we pick, it cannot be determined. Option E is correct.

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