Multiple choice

In each of these questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 + 14x = -49) II. (y^2 = 9y)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation I: x^2 + 14x + 49 = 0 gives (x+7)^2 = 0, so x = -7 (repeated root). Solving equation II: y^2 - 9y = 0 gives y(y-9) = 0, so y = 0 or y = 9. Comparing: -7 < 0 and -7 < 9, meaning x is always less than y.

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