In each of the following questions (I) and (II) equations are given. You have to solve them and Give answer- (I)(3x^2 + 23x + 30 = 0) (II) (6y^2 + 13y + 5 = 0)

Solving 3x²+23x+30=0: factors as (3x+20)(x+1.5)=0, giving x=-20/3≈-6.67 or x=-1.5. Solving 6y²+13y+5=0: factors as (2y+1)(3y+5)=0, giving y=-1/2=-0.5 or y=-5/3≈-1.67. Checking all combinations: -6.67<-0.5, -6.67<-1.67, -1.5<-0.5, and -1.5>-1.67. Since some x values are less than some y values and some are greater, but x is never always greater than y, the most accurate relationship is x≤y (since the maximum x value -1.5 is less than or equal to -0.5).