Multiple choice

In each of the following questions (I) and (II) equations are given. You have to solve them and Give answer- (I) (x^2 + 3x - 28 = 0)() (II) (y^2 - 11y + 28 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be determined
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation (I): x² + 3x - 28 = 0 gives x = -7 or x = 4. Solving equation (II): y² - 11y + 28 = 0 gives y = 7 or y = 4. Checking all combinations: when x = -7, x < y (for y = 7 or 4); when x = 4, x ≤ y (x = y when y = 4, x < y when y = 7). In all cases, x ≤ y holds true. Option A (x > y) and C (x < y) are incorrect because they don't cover all cases. Option B (x ≥ y) fails when x = -7.

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