Multiple choice

If a coin is tossed 6 times randomly, then the methods of finding 4 heads and 2 tails of the same coin will be:

  1. $8$
  2. $11$
  3. $15$
  4. $19$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The number of ways to get exactly 4 heads and 2 tails in 6 tosses is given by combinations: 6C4 = 6!/(4!×2!) = (6×5)/(2×1) = 15. This counts all arrangements of 4 H's and 2 T's regardless of order. Each arrangement like HHHHTT, HHTHHT, etc. is counted once.