Multiple choice

In the given question two equations I & II are given, you have to solve them and answer the question.(\text{(I)}) (3x^2 + 8x + 5 = 0) (\text{(II)}) (10y^2 + 9y + 2 = 0)

  1. if x > y

  2. if x < y

  3. if x = y or relation can’t be establish

  4. if x ≥ y

  5. if x ≤ y
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation (I): 3x^2 + 8x + 5 = 0 factors to (3x+5)(x+1) = 0, giving x = -5/3 or x = -1. Solving equation (II): 10y^2 + 9y + 2 = 0 factors to (5y+2)(2y+1) = 0, giving y = -2/5 or y = -1/2. Converting to decimals: x values are -1.67 and -1; y values are -0.4 and -0.5. In all combinations, y values (closer to zero) are greater than x values.

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