Multiple choice

In the following question two equations I and II are given. You have to solve both the equations and give answer.(I) \ 16x^2 – 8x + 1 = 0 (II) \ y^2 + 0.9y – 0.22 = 0

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Equation I: 16x²-8x+1=0 factors as (4x-1)²=0, so x = 1/4 = 0.25 (repeated root). Equation II: y²+0.9y-0.22=0 uses quadratic formula: y = (-0.9 ± √(0.81+0.88))/2 = (-0.9 ± √1.69)/2 = (-0.9 ± 1.3)/2, giving y = 0.2 or y = -1.1. Since x=0.25 is greater than both y=0.2 and y=-1.1, x > y always. Option A is correct. Option E would be wrong because the relationship is clearly determined.

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