Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer.( (I) ) (x^2 - 7x + 12 = 0) ( (II) ) (2y^2 + 18y + 36 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.
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A Correct answer
Explanation

Solving equation (I): x² - 7x + 12 = 0 factors to (x-3)(x-4) = 0, so x = 3 or x = 4. Solving equation (II): 2y² + 18y + 36 = 0 simplifies to y² + 9y + 18 = 0, which factors to (y+3)(y+6) = 0, so y = -3 or y = -6. Both values of x (3 and 4) are greater than both values of y (-3 and -6), so x > y is always true.

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