In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 – 3.5x + 3 = 0) II. (y^2 – 5.5y + 7 = 0)$

Solving x² - 3.5x + 3 = 0 using quadratic formula: x = (3.5 ± √0.25)/2 = (3.5 ± 0.5)/2, giving x = 2 or x = 1.5. Solving y² - 5.5y + 7 = 0: y = (5.5 ± √2.25)/2 = (5.5 ± 1.5)/2, giving y = 3.5 or y = 2. Comparing all pairs: x ∈ {1.5, 2} and y ∈ {2, 3.5}. The maximum value of x is 2 and the minimum value of y is 2, so x is always less than or equal to y.