Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 - 9 = 0) II. (y^2 - 16 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving the first equation: x² = 9, so x = ±3. Solving the second: y² = 16, so y = ±4. The possible pairs are (3, 4), (3, -4), (-3, 4), (-3, -4). This gives x > y (when x=3, y=-4), x < y (when x=-3, y=4 or x=3, y=4), and x < y (when x=-3, y=4). Since x can be both greater than and less than y depending on which roots we choose, the relationship cannot be uniquely determined.

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