Multiple choice

In each of the following questions two equations are given. You have to solve both the equation and state the correct relationship. $I. (4y^2 + 9y + 2 = 0)$ $II. (15x^2 - 32x + 16 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or the relationship can not be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: 4y²+9y+2=0 factors to (4y+1)(y+2)=0, so y=-1/4 or y=-2. Solving equation II: 15x²-32x+16=0 factors to (5x-4)(3x-4)=0, so x=4/5 or x=4/3. Comparing values: x is always positive (4/5 or 4/3), y is always negative (-1/4 or -2). Therefore, x > y.

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