Multiple choice

In each of the following questions two equations are given. You have to solve both the equation and state the correct relationship. $I. (14x^2 + 15x + 4 = 0)$ $II. (14y^2 + 29y + 12 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation I: 14x²+15x+4=0 factors to (7x+4)(2x+1)=0, so x=-4/7 or x=-1/2. Solving equation II: 14y²+29y+12=0 factors to (7y+4)(2y+3)=0, so y=-4/7 or y=-3/2. Comparing values: when x=-4/7, x≥y (equal to -4/7, greater than -3/2). When x=-1/2, x≥y (greater than both -4/7 and -3/2). Therefore, x ≥ y.

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