Multiple choice

In each of the following questions two equations are given. You have to solve both the equation and state the correct relationship. $I. (4x^2 - 8x + 3 = 0)$ $II. (12y^2 - 7y + 1 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or the relationship can not be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: 4x²-8x+3=0 factors to (2x-3)(2x-1)=0, so x=3/2 or x=1/2. Solving equation II: 12y²-7y+1=0 factors to (3y-1)(4y-1)=0, so y=1/3 or y=1/4. Comparing values: x=3/2 or 1/2, y=1/3 or 1/4. In all cases, x > y. Therefore, x > y.

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