Multiple choice

If a man drives at 25\% more than of his usual speed then he reaches 15 minutes earlier. Find his usual time taken to cover the same distance?

  1. 1 hr.35minutes

  2. 1 hr.25 minutes

  3. 1 hr.15 minutes

  4. 1 hr.45 minutes

  5. None of these
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Let usual speed = S, usual time = T. Distance = S × T. New speed = 1.25S (25% more). New time = Distance/(1.25S) = T/1.25 = 0.8T. Time saved = T - 0.8T = 0.2T = 15 minutes. So T = 15/0.2 = 75 minutes = 1 hour 15 minutes. Option C is correct.

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