Multiple choice

Find the value of both quantities and state the correct relationship. Quantity I: Age of father, if age of Abhinav is 1/3th of his father’s and 10 years after Abhinav’s age becomes half of his father’s age. Quantity II: Age of father, if 5 years ago age of A’s father was three times the age of A and 5 years hence his age will be double A’s age.

  1. Quantity I > Quantity II

  2. Quantity I ≥ Quantity II

  3. Quantity II > Quantity I

  4. Quantity II ≥ Quantity I

  5. Quantity I = Quantity II or Relation cannot be established
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C Correct answer
Explanation

Quantity I: Let Abhinav's age = x, father's age = 3x. After 10 years: (x+10) = (1/2)(3x+10). Solving: 2x + 20 = 3x + 10, so x = 10. Father's age = 30 years. Quantity II: 5 years ago: father = 3 × A. 5 years hence: father = 2 × A. Let current ages be F and A. (F-5) = 3(A-5) and (F+5) = 2(A+5). From first: F = 3A - 10. Substituting: 3A - 5 = 2A + 10, so A = 15, F = 35. Father's age = 35 years. Clearly 35 > 30, so Quantity II is greater.

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