Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and give answer. $(I) (7x^2 - 41x + 30 = 0)$ $(II) (7y^2 - 26y + 24 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For equation (I): 7x²-41x+30=0 gives x=5 or x=6/7≈0.86. For equation (II): 7y²-26y+24=0 gives y=2 or y=12/7≈1.71. When x=5, x>y. When x=6/7≈0.86, x

Keep practicing — related questions