Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and give answer. $( (I) \quad 2x^2 – 17x + 36 = 0 \ (II) \quad 15y^2 – 16y + 4 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
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A Correct answer
Explanation

For equation (I): 2x²-17x+36=0 gives x=4.5 or x=4. For equation (II): 15y²-16y+4=0 gives y=2/3 or y=2/5. Since all values of x (4, 4.5) are greater than all values of y (0.4, 0.67), we conclude x > y.

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