Multiple choice

In the following question two equations I and II are given. You have to solve both the equations and give answer. $( (I) \ (x + 3)^{2} - 25 = 0 )$ $( (II) \ y^{2} - 14y + 49 = 0 )$

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or the relationship cannot be determined
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving (I): (x+3)²-25=0 gives x = -8, 2. Solving (II): y²-14y+49=0 gives (y-7)²=0, so y = 7 (repeated root). For all combinations: -8 < 7, 2 < 7. Therefore x < y always, so answer is A.

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