Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $( (I) \ 2x^2 + 13x + 20 = 0 \ (II) \ 2y^2 - 7y - 4 = 0 )$

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or the relationship cannot be determined
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving (I): 2x²+13x+20=0 gives x = -2.5, -4. Solving (II): 2y²-7y-4=0 gives y = -0.5, 4. For all combinations: -2.5 < -0.5, -2.5 < 4, -4 < -0.5, -4 < 4. Therefore x < y always, so answer is A.

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