Multiple choice

In each of the following questions, two equations are given. You have to solve them and state the correct relationship- $I. (x^2 + 14x + 49 = 0) II. (y^2 + 9y = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: x² + 14x + 49 = 0 factors as (x + 7)² = 0, giving x = -7. Equation II: y² + 9y = 0 factors as y(y + 9) = 0, giving y = 0 or y = -9. When x = -7 and y = 0, x < y. When x = -7 and y = -9, x > y. Since both relationships are possible, no single relationship can be established.

Keep practicing — related questions