Multiple choice

In the following questions two equations numbered (I) and (II) are given. You have to solve both equations and give answer— $(I) (16x^2 + 20x + 6 = 0) (II) (10y^2 + 38y + 24 = 0)$

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \leq y\)$
  4. $\(x \geq y\)$

  5. x=y or relation cannot be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation (I): 16x² + 20x + 6 = 0 gives x = -0.5 or x = -0.75. Solving equation (II): 10y² + 38y + 24 = 0 gives y = -0.8 or y = -3. Both values of x (-0.5, -0.75) are greater than both values of y (-0.8, -3), so x > y is always true. Option C (x ≤ y) is false because x is never less than or equal to y.

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