Multiple choice

In each of the following questions, two equations are given. You have to solve them and give answer. (I) (2x^2 + 22x + 56 = 0) (II) (y^2 + 12y + 35 = 0)

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation (I): 2x²+22x+56=0 simplifies to x²+11x+28=0, factoring as (x+4)(x+7)=0, giving x=-4 or x=-7. Solving equation (II): y²+12y+35=0 factors as (y+5)(y+7)=0, giving y=-5 or y=-7. When x=-7 and y=-7, x=y. When x=-4 and y=-5, x>y. When x=-4 and y=-7, x>y. When x=-7 and y=-5, xy, sometimes x

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