Multiple choice

In each of the following questions, two equations are given. You have to solve them and $( (i) 3x^2 - 16x + 21 = 0 )\n( (ii) 6y^2 + 5y + 21 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving 3x²-16x+21=0 gives x=7/3≈2.33 and x=3. The equation 6y²+5y+21=0 has discriminant 25-504=-479 < 0, so y has no real values. Since all real x values are greater than non-existent real y values, x>y.

Keep practicing — related questions