Multiple choice

Solve the following equations and determine the relationship between (x) and (y): (i) (3x^2 - 16x + 21 = 0) (ii) (6y^2 + 5y + 21 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can't be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solve both equations: 3x²-16x+21=0 gives x=(16±√(256-252))/6=(16±2)/6, so x=3 or x≈2.33. For 6y²+5y+21=0, the discriminant is 25-504=-479, which is negative, meaning y has no real solutions (it's imaginary). Therefore, all real x values are greater than imaginary y values, so x > y. The claimed answer (A) is correct.

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