Multiple choice

In each of the following questions, two equations are given you have to solve them and. (i) (x^2 + 21x - 46 = 0) (ii) (y^2 + 4y - 81 = 0) Give answer

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can't be established.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve both equations: x²+21x-46=0 gives x=(-21±√(441+184))/2=(-21±√625)/2=(-21±25)/2, so x=2 or x=-23. y²+4y-81=0 gives y=(-4±√(16+324))/2=(-4±√340)/2=(-4±18.44)/2, so y≈7.22 or y≈-11.22. Since x can be 2 (less than 7.22 but greater than -11.22) or -23 (less than both y values), and y has irrational values, no clear relationship can be established.

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