Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer-\newlineI. (15x^2 + 18x + 3 = 0)\newlineII. (12.5y^2 - 24y + 16 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relation can't be determined
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Equation I: 15x² + 18x + 3 = 0. Dividing by 3: 5x² + 6x + 1 = 0. Factorizing: (5x + 1)(x + 1) = 0. So x = -1/5 or x = -1. Equation II: 12.5y² - 24y + 16 = 0. Multiplying by 2: 25y² - 48y + 32 = 0. Factorizing: (5y - 8)(5y - 4) = 0. So y = 8/5 = 1.6 or y = 4/5 = 0.8. When x = -1 or -0.2 and y = 0.8 or 1.6, we have x < y in both cases. Therefore x ≤ y is correct.

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