If the area of isosceles triangle ABC is 108 cm.2 and distance of base BC from centroid is 6 cm. and length of equal sides are 6 10 cm. find the length of base. यदि समद्विबाहु त्रिभुज ABC का क्षेत्रफल 108 सेमी.2 है और आधार BC केन्द्रक से 6 सेमी. तथा बराबर भुजाओ की लंबाई 6 10 सेमी. है। तो आधार की लंबाई क्या होगी?
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6 cm./सेमी.
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12 cm./सेमी.
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18 cm./सेमी.
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24 cm./सेमी.
B
Correct answer
Explanation
Area of triangle ABC = 108 cm². Distance of base BC from centroid G = 6 cm. The centroid divides the median in ratio 2:1, so the height h from A to BC satisfies h/3 = 6, giving h = 18 cm. Area = (1/2) × base × height = (1/2) × b × 18 = 108, so base b = 108 × 2/18 = 12 cm. The equal sides' information is consistent but not needed for this calculation.