Multiple choice

In each of the following questions, two equations I and II are given. You have to solve them and $I. ( x = (729)^{1/3} ) II. ( y^2 = 81 )$ Give answer

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation I: x = (729)^(1/3) = 9 (since 9³ = 729). Solving equation II: y² = 81, so y = ±9. Therefore x = 9 and y can be 9 or -9. This means x ≥ y (x is greater than or equal to y, since 9 ≥ 9 and 9 ≥ -9).

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