Multiple choice

In each of the following questions, two equations are given. You have to solve them and $I. (x^2 - 5x + 6 = 0) II. (y^2 - 9y + 14 = 0)$ Give answer

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve both quadratic equations. For x^2 - 5x + 6 = 0, factors are (x-2)(x-3)=0, so x = 2 or 3. For y^2 - 9y + 14 = 0, factors are (y-2)(y-7)=0, so y = 2 or 7. Since x can be 2 or 3 and y can be 2 or 7, x ≤ y is always true (when x=2, y=2 or 7; when x=3, y=7).

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