Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and $(I. \quad 3x + 4y = 16 )$ $(II. \quad 2x + 2y = 9)$ Given answer-

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relation can't be determined
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

I: 3x + 4y = 16. II: 2x + 2y = 9. From II: divide by 2: x + y = 4.5, so x = 4.5 - y. Substitute in I: 3(4.5-y) + 4y = 16 → 13.5 - 3y + 4y = 16 → y = 2.5. Then x = 4.5 - 2.5 = 2. So x = 2, y = 2.5, meaning x < y.

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