Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 - 12x + 35 = 0) II. (y^2 - 9y + 20 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined.

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve both equations: x² - 12x + 35 = 0 gives (x-5)(x-7) = 0, so x = 5 or 7. y² - 9y + 20 = 0 gives (y-4)(y-5) = 0, so y = 4 or 5. Comparing all combinations: when x=5, y can be 4 or 5 (5≥4, 5≥5); when x=7, y can be 4 or 5 (7≥4, 7≥5). In all cases, x ≥ y is true.