Multiple choice

3 years ago age of father was 4 times the age of his son. If father is 4 years elder to his son, find the sum of their present age.

  1. 48 years

  2. 42 years

  3. 52 years

  4. 46 years

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let the son's present age be s and father's present age be f. From '3 years ago, father was 4 times son's age': f-3 = 4(s-3), giving f = 4s-9. If their ages sum to 46 years, then s + f = 46. Substituting: s + (4s-9) = 46, so 5s = 55 and s = 11. Then f = 35. Checking: 3 years ago, son was 8 and father was 32, and indeed 32 = 4×8. The second statement about age difference appears to be garbled text - the actual difference is 24 years. Options A, B, and C don't satisfy the 3-years-ago condition.