Multiple choice

A point P is 26 cm. away from the center O of a circle and PT is the tangent drawn from P to the circle is 10 cm., then OT is equal to - एक बिन्दु P एक वृत्त के केन्द्र से 26 सेमी. दूरी पर है और PT स्पर्श रेखा P से 10 सेमी. की खींची गई है। तो OT बराबर है-

  1. 18 cm./सेमी.

  2. 20 cm./सेमी.

  3. 24 cm./सेमी.

  4. 36 cm./सेमी.
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C Correct answer
Explanation

By tangent-secant theorem: PT² = OP² - OT² (since OT ⟂ PT). Given OP = 26 cm and PT = 10 cm, we have OT² = 26² - 10² = 676 - 100 = 576. Thus OT = √576 = 24 cm. The radius is perpendicular to the tangent at the point of contact.

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