Multiple choice

In each of the following questions, two equations are given. You have to solve them and $(I. \quad x^2 – x – 6 = 0 \ II. \quad 2y^2 + 13y + 21 = 0)$

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established
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A Correct answer
Explanation

I: x² - x - 6 = 0 gives (x - 3)(x + 2) = 0, so x = 3 or -2. II: 2y² + 13y + 21 = 0 gives (2y + 7)(y + 3) = 0, so y = -7/2 = -3.5 or -3. Comparing: when x = 3, x > y (both -3.5 and -3). When x = -2, x > y (both -3.5 and -3). Therefore x > y.

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