Multiple choice

In each of the following questions, two equations are given. You have to solve them and $( (I) \ 12x^2 - 7x + 1 = 0 ) ( (II) \ 15y^2 - 16y + 4 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve equation (I): 12x² - 7x + 1 = 0. Using quadratic formula: x = (7 ± √(49 - 48)) / 24 = (7 ± 1) / 24. So x = 8/24 = 1/3 or x = 6/24 = 1/4. Values are x = 0.33 or x = 0.25. For equation (II): 15y² - 16y + 4 = 0. Using formula: y = (16 ± √(256 - 240)) / 30 = (16 ± 4) / 30. So y = 20/30 = 2/3 ≈ 0.667 or y = 12/30 = 2/5 = 0.4. Comparing: x (0.33 or 0.25) < y (0.667 or 0.4). Therefore x < y is correct.

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