Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the question and give answer if - $(I. \quad x^2 - 9x + 20 = 0 \ II. \quad y^2 - 13y + 42 = 0)$

  1. $\(x > y\)$
  2. $\(x \ge y\)$
  3. $\(x < y\)$
  4. $\(x \le y\)$

  5. x = y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: x²-9x+20=0 factors to (x-4)(x-5)=0, so x=4 or 5. Equation II: y²-13y+42=0 factors to (y-6)(y-7)=0, so y=6 or 7. All values of y (6,7) are greater than all values of x (4,5). Therefore x < y is always true. Option C is correctly marked.

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