Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 + 8x + 15 = 0)$ $II. (y^2 + 11y + 30 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relation cannot be determined.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve x²+8x+15=0: (x+3)(x+5)=0, so x=-3,-5. Solve y²+11y+30=0: (y+5)(y+6)=0, so y=-5,-6. Compare: x=-3 > y=-5,-6 always. x=-5 = y=-5 possible, x=-5 > y=-6. Thus x ≥ y holds in all cases.

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