Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (2x + 4y = 13)$ $II. (4x + 2y = 14)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relation cannot be determined.
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A Correct answer
Explanation

Solving the system: 2x+4y=13 and 4x+2y=14. Multiply first equation by 2: 4x+8y=26. Subtract second equation: (4x+8y)-(4x+2y)=26-14 gives 6y=12, so y=2. Substitute: 2x+8=13, x=2.5. Thus x=2.5 > y=2.

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