Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $I. (x^2 + 3x + 2 = 0) II. (y^2 + 5y + 6 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relation cannot be determined.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve x²+3x+2=0 gives x=-1,-2. Solve y²+5y+6=0 gives y=-2,-3. So x can be -1 or -2, y can be -2 or -3. When x=-1, x>-2 and x>-3. When x=-2, x=-2=y is possible, x>-3. Thus x ≥ y always holds.

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