Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and- $( (I) x^2 + 17x + 30 = 0 )$ $( (II) y^2 - 13y = -30 )$ Give answer

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving equation (I): x² + 17x + 30 = 0. Factor: (x + 15)(x + 2) = 0, so x = -15 or x = -2. Solving equation (II): y² - 13y = -30, so y² - 13y + 30 = 0. Factor: (y - 10)(y - 3) = 0, so y = 10 or y = 3. Comparing values: x values are -15 and -2 (both negative), y values are 10 and 3 (both positive). Therefore x < y for all possible combinations, making answer C correct.

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