Multiple choice

(\text{Solve the following equations and determine the relationship between x and y:})\n(\text{(I)}\quad x^2 + 9x + 18 = 0 )\n(\text{(II)}\quad y^2 - 13y + 40 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: x² + 9x + 18 = 0 gives (x+6)(x+3) = 0, so x = -6 or -3. Equation II: y² - 13y + 40 = 0 gives (y-8)(y-5) = 0, so y = 8 or 5. All values of x are negative (-6, -3) while all values of y are positive (8, 5). Therefore x < y is always true regardless of which specific root values we compare.

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