Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and give answer.( (I) ) ( x^2 + x - 12 = 0 ) ( (II) ) ( y^2 - 5y + 6 = 0 )

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: x² + x - 12 = 0 gives (x+4)(x-3) = 0, so x = -4 or 3. Equation II: y² - 5y + 6 = 0 gives (y-2)(y-3) = 0, so y = 2 or 3. Comparing all possible pairs: when x=-4, xy when y=2. Since the relationship varies depending on which root values we choose, it cannot be established.

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