In a circle of radius 3 units, a diameter AB intersects a chord of Length 3 units. perpendicularly at P. If AP > BP, then AP is equal to approximately. 3 इकाई त्रिज्या के एक वृत्त में व्यास AB एक 3 इकाई की जीवा को लम्बवत् बिन्दु P पर काटता है। यदि AP>BP तो AP का लगभग मान है-

Let O be center, AB is diameter (length 6). Let chord CD = 3, perpendicular to AB at P. If AP > BP, then AP > 3. By chord theorem: CP × PD = AP × BP. Since P is midpoint of chord (perpendicular from center bisects chord), CP = PD = 3/2 = 1.5. So 1.5² = AP × BP = AP × (6-AP). 2.25 = 6AP - AP². AP² - 6AP + 2.25 = 0. AP = (6 ± √(36-9))/2 = (6 ± √27)/2 = (6 ± 5.196)/2. AP = 5.598 or AP = 0.402. Since AP > BP, AP > 3, so AP ≈ 5.6, matching option B.