Multiple choice

In each of these questions two equations are given. You have to solve these equations and find out the value of x and y and give the answer. $( (I) \quad 4x + 3y – 16 = 0 ) ( (II) \quad 2x + 2y – 9 = 0 )$

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or if the relation cannot be established.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve the system: 4x + 3y = 16 and 2x + 2y = 9. Multiply the second equation by 2 to get 4x + 4y = 18. Subtract the first equation: (4x + 4y) - (4x + 3y) = 18 - 16, giving y = 2. Substitute back: 2x + 2(2) = 9, so 2x = 5 and x = 2.5. Since x = 2.5 and y = 2, we have x > y.

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