Multiple choice

In each of these questions two equations are given. You have to solve these equations and find out the value of x and y and give the answer.(\text{(I)}) (x^2 + 7x + 12 = 0) (\text{(II)}) (y^2 + 5y + 6 = 0)

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. x = y or if the relation cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation (I): x² + 7x + 12 = 0 factors to (x+3)(x+4)=0, so x = -3 or -4. Equation (II): y² + 5y + 6 = 0 factors to (y+2)(y+3)=0, so y = -2 or -3. Comparing all pairs: (-3,-2) gives x

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